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3-2x^2=7x
We move all terms to the left:
3-2x^2-(7x)=0
a = -2; b = -7; c = +3;
Δ = b2-4ac
Δ = -72-4·(-2)·3
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{73}}{2*-2}=\frac{7-\sqrt{73}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{73}}{2*-2}=\frac{7+\sqrt{73}}{-4} $
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